(5b+8)(b+6)=0

Solution for (5b+8)(b+6)=0 equation:

(5b+8)(b+6)=0

We multiply parentheses ..

(+5b^2+30b+8b+48)=0

We get rid of parentheses

5b^2+30b+8b+48=0

We add all the numbers together, and all the variables

5b^2+38b+48=0

a = 5; b = 38; c = +48;
Δ = b2-4ac
Δ = 382-4·5·48
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-22}{2*5}=\frac{-60}{10}
=-6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+22}{2*5}=\frac{-16}{10}
=-1+3/5
$