(5b+2)+(4m+4)=

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Solution for (5b+2)+(4m+4)= equation:


Simplifying
(5b + 2) + (4m + 4) = 0

Reorder the terms:
(2 + 5b) + (4m + 4) = 0

Remove parenthesis around (2 + 5b)
2 + 5b + (4m + 4) = 0

Reorder the terms:
2 + 5b + (4 + 4m) = 0

Remove parenthesis around (4 + 4m)
2 + 5b + 4 + 4m = 0

Reorder the terms:
2 + 4 + 5b + 4m = 0

Combine like terms: 2 + 4 = 6
6 + 5b + 4m = 0

Solving
6 + 5b + 4m = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + 5b + -6 + 4m = 0 + -6

Reorder the terms:
6 + -6 + 5b + 4m = 0 + -6

Combine like terms: 6 + -6 = 0
0 + 5b + 4m = 0 + -6
5b + 4m = 0 + -6

Combine like terms: 0 + -6 = -6
5b + 4m = -6

Add '-4m' to each side of the equation.
5b + 4m + -4m = -6 + -4m

Combine like terms: 4m + -4m = 0
5b + 0 = -6 + -4m
5b = -6 + -4m

Divide each side by '5'.
b = -1.2 + -0.8m

Simplifying
b = -1.2 + -0.8m

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