(5a+3b-6c)+(2a-4b+13c)=0

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Solution for (5a+3b-6c)+(2a-4b+13c)=0 equation:


Simplifying
(5a + 3b + -6c) + (2a + -4b + 13c) = 0

Remove parenthesis around (5a + 3b + -6c)
5a + 3b + -6c + (2a + -4b + 13c) = 0

Remove parenthesis around (2a + -4b + 13c)
5a + 3b + -6c + 2a + -4b + 13c = 0

Reorder the terms:
5a + 2a + 3b + -4b + -6c + 13c = 0

Combine like terms: 5a + 2a = 7a
7a + 3b + -4b + -6c + 13c = 0

Combine like terms: 3b + -4b = -1b
7a + -1b + -6c + 13c = 0

Combine like terms: -6c + 13c = 7c
7a + -1b + 7c = 0

Solving
7a + -1b + 7c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'b' to each side of the equation.
7a + -1b + b + 7c = 0 + b

Combine like terms: -1b + b = 0
7a + 0 + 7c = 0 + b
7a + 7c = 0 + b
Remove the zero:
7a + 7c = b

Add '-7c' to each side of the equation.
7a + 7c + -7c = b + -7c

Combine like terms: 7c + -7c = 0
7a + 0 = b + -7c
7a = b + -7c

Divide each side by '7'.
a = 0.1428571429b + -1c

Simplifying
a = 0.1428571429b + -1c

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