(5L+2c)(5L-2c)=

Solution for (5L+2c)(5L-2c)= equation:

Simplifying
(5L + 2c)(5L + -2c) = 0

Multiply (5L + 2c) * (5L + -2c)
(5L * (5L + -2c) + 2c * (5L + -2c)) = 0
((5L * 5L + -2c * 5L) + 2c * (5L + -2c)) = 0
((25L2 + -10cL) + 2c * (5L + -2c)) = 0
(25L2 + -10cL + (5L * 2c + -2c * 2c)) = 0
(25L2 + -10cL + (10cL + -4c2)) = 0

Combine like terms: -10cL + 10cL = 0
(25L2 + 0 + -4c2) = 0
(25L2 + -4c2) = 0

Solving
25L2 + -4c2 = 0

Solving for variable 'L'.

Move all terms containing L to the left, all other terms to the right.

Add '4c2' to each side of the equation.
25L2 + -4c2 + 4c2 = 0 + 4c2

Combine like terms: -4c2 + 4c2 = 0
25L2 + 0 = 0 + 4c2
25L2 = 0 + 4c2
Remove the zero:
25L2 = 4c2

Divide each side by '25'.
L2 = 0.16c2

Simplifying
L2 = 0.16c2

Take the square root of each side:
L = {-0.4c, 0.4c}