(50x2)+x=1000

Solution for (50x2)+x=1000 equation:

(50x^2)+x=1000

We move all terms to the left:

(50x^2)+x-(1000)=0

a = 50; b = 1; c = -1000;
Δ = b2-4ac
Δ = 12-4·50·(-1000)
Δ = 200001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{200001}}{2*50}=\frac{-1-\sqrt{200001}}{100}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{200001}}{2*50}=\frac{-1+\sqrt{200001}}{100}
$