(5/y)+(1/y)=2

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Solution for (5/y)+(1/y)=2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

5/y+1/y = 2 // - 2

5/y+1/y-2 = 0

6*y^-1 = 2 // : 6

y^-1 = 1/3

-1 < 0

1/(y^1) = 1/3 // * y^1

1 = 1/3*y^1 // : 1/3

3 = y^1

y = 3

y = 3

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