(5/x)-(8/3)=(1/12x)

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Solution for (5/x)-(8/3)=(1/12x) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x-(8/3) = (1/12)*x // - (1/12)*x

5/x-((1/12)*x)-(8/3) = 0

(-1/12)*x+5/x-8/3 = 0

5*x^-1-1/12*x^1-8/3*x^0 = 0

(5*x^0-1/12*x^2-8/3*x^1)/(x^1) = 0 // * x^2

x^1*(5*x^0-1/12*x^2-8/3*x^1) = 0

x^1

(-1/12)*x^2+(-8/3)*x+5 = 0

(-1/12)*x^2+(-8/3)*x+5 = 0

DELTA = (-8/3)^2-(4*5*(-1/12))

DELTA = 79/9

DELTA > 0

x = ((79/9)^(1/2)-(-8/3))/(2*(-1/12)) or x = (-(-8/3)-(79/9)^(1/2))/(2*(-1/12))

x = -6*((79/9)^(1/2)+8/3) or x = -6*(8/3-(79/9)^(1/2))

x in { -6*((79/9)^(1/2)+8/3), -6*(8/3-(79/9)^(1/2))}

x in { -6*((79/9)^(1/2)+8/3), -6*(8/3-(79/9)^(1/2)) }

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