(5/v-5)-(6/v+1)=(29/(v2-4v-5))

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Solution for (5/v-5)-(6/v+1)=(29/(v2-4v-5)) equation: 



(5/v-5)-(6/v+1)=(29/(v2-4v-5))

We move all terms to the left:

(5/v-5)-(6/v+1)-((29/(v2-4v-5)))=0



Domain of the equation: v-5)!=0

v∈R





Domain of the equation: v+1)!=0

v∈R





Domain of the equation: (v2-4v-5)))!=0

v∈R



We add all the numbers together, and all the variables

-((29/(+v^2-4v-5)))+(5/v-5)-(6/v+1)=0

We get rid of parentheses

-((29/(+v^2-4v-5)))+5/v-6/v-5-1=0

We calculate fractions

We do not support evpression: v^3

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