(5/7)(x-9)=25

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Solution for (5/7)(x-9)=25 equation: 



(5/7)(x-9)=25

We move all terms to the left:

(5/7)(x-9)-(25)=0



Domain of the equation: 7)(x-9)!=0

x∈R



We add all the numbers together, and all the variables

(+5/7)(x-9)-25=0

We multiply parentheses ..

(+5x^2+5/7*-9)-25=0

We multiply all the terms by the denominator


(+5x^2+5-25*7*-9)=0

We get rid of parentheses

5x^2+5-9-25*7*=0

We add all the numbers together, and all the variables

5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$

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