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(5/6)y=5/24
We move all terms to the left:
(5/6)y-(5/24)=0
Domain of the equation: 6)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+5/6)y-(+5/24)=0
We multiply parentheses
5y^2-(+5/24)=0
We get rid of parentheses
5y^2-5/24=0
We multiply all the terms by the denominator
5y^2*24-5=0
Wy multiply elements
120y^2-5=0
a = 120; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·120·(-5)
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{6}}{2*120}=\frac{0-20\sqrt{6}}{240} =-\frac{20\sqrt{6}}{240} =-\frac{\sqrt{6}}{12} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{6}}{2*120}=\frac{0+20\sqrt{6}}{240} =\frac{20\sqrt{6}}{240} =\frac{\sqrt{6}}{12} $
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