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(5/6)x-4x+4/3=5/3
We move all terms to the left:
(5/6)x-4x+4/3-(5/3)=0
Domain of the equation: 6)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+5/6)x-4x+4/3-(+5/3)=0
We add all the numbers together, and all the variables
-4x+(+5/6)x+4/3-(+5/3)=0
We multiply parentheses
5x^2-4x+4/3-(+5/3)=0
We get rid of parentheses
5x^2-4x+4/3-5/3=0
We multiply all the terms by the denominator
5x^2*3-4x*3+4-5=0
We add all the numbers together, and all the variables
5x^2*3-4x*3-1=0
Wy multiply elements
15x^2-12x-1=0
a = 15; b = -12; c = -1;
Δ = b2-4ac
Δ = -122-4·15·(-1)
Δ = 204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{204}=\sqrt{4*51}=\sqrt{4}*\sqrt{51}=2\sqrt{51}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{51}}{2*15}=\frac{12-2\sqrt{51}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{51}}{2*15}=\frac{12+2\sqrt{51}}{30} $
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