(5/6)x+(2/3)=-9

Solution for (5/6)x+(2/3)=-9 equation:

(5/6)x+(2/3)=-9

We move all terms to the left:

(5/6)x+(2/3)-(-9)=0


Domain of the equation: 6)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+5/6)x+(+2/3)-(-9)=0

We add all the numbers together, and all the variables

(+5/6)x+9+(+2/3)=0

We multiply parentheses

5x^2+9+(+2/3)=0

We get rid of parentheses

5x^2+9+2/3=0

We multiply all the terms by the denominator


5x^2*3+2+9*3=0

We add all the numbers together, and all the variables

5x^2*3+29=0

Wy multiply elements

15x^2+29=0

a = 15; b = 0; c = +29;
Δ = b2-4ac
Δ = 02-4·15·29
Δ = -1740
Delta is less than zero, so there is no solution for the equation