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(5/6)(y)-9=-4
We move all terms to the left:
(5/6)(y)-9-(-4)=0
Domain of the equation: 6)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+5/6)y-9-(-4)=0
We add all the numbers together, and all the variables
(+5/6)y-5=0
We multiply parentheses
5y^2-5=0
a = 5; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·5·(-5)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*5}=\frac{-10}{10} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*5}=\frac{10}{10} =1 $
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