(5/6)(12z-24)=(2/5)(25z-25)

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Solution for (5/6)(12z-24)=(2/5)(25z-25) equation: 


z in (-oo:+oo)

(5/6)*(12*z-24) = (2/5)*(25*z-25) // - (2/5)*(25*z-25)

(5/6)*(12*z-24)-((2/5)*(25*z-25)) = 0

(5/6)*(12*z-24)+(-2/5)*(25*z-25) = 0

5/6*(12*z-24)-2/5*(25*z-25) = 0

5/6*(12*z-24)-2/5*(25*z-25) = 0

-10 = 0

-10 = 0

z belongs to the empty set

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