(5/5-x)-(4/x-7)=0

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Solution for (5/5-x)-(4/x-7)=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5/5-x-(4/x)+7 = 0

5/5-x-4*x^-1+7 = 0

8*x^0-1*x^1-4*x^-1 = 0

(8*x^1-1*x^2-4*x^0)/(x^1) = 0 // * x^2

x^1*(8*x^1-1*x^2-4*x^0) = 0

x^1

8*x-x^2-4 = 0

8*x-x^2-4 = 0

DELTA = 8^2-(-4*(-1)*4)

DELTA = 48

DELTA > 0

x = (48^(1/2)-8)/(-1*2) or x = (-48^(1/2)-8)/(-1*2)

x = (4*3^(1/2)-8)/(-2) or x = (-4*3^(1/2)-8)/(-2)

x in { (4*3^(1/2)-8)/(-2), (-4*3^(1/2)-8)/(-2)} 

x in { (4*3^(1/2)-8)/(-2), (-4*3^(1/2)-8)/(-2) }

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