(5/4)y-1=(7/3)y-2

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Solution for (5/4)y-1=(7/3)y-2 equation:



(5/4)y-1=(7/3)y-2
We move all terms to the left:
(5/4)y-1-((7/3)y-2)=0
Domain of the equation: 4)y!=0
y!=0/1
y!=0
y∈R
Domain of the equation: 3)y-2)!=0
y!=0/1
y!=0
y∈R
We add all the numbers together, and all the variables
(+5/4)y-((+7/3)y-2)-1=0
We multiply parentheses
5y^2-((+7/3)y-2)-1=0
We multiply all the terms by the denominator
5y^2*3)y-2)-((-1*3)y-2)+7=0
We add all the numbers together, and all the variables
5y^2*3)y-2)-((-3)y-2)+7=0
Wy multiply elements
15y^3-3)y-2)+7=0
We do not support eypression: y^3

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