(5/4)c+12=2

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Solution for (5/4)c+12=2 equation: 



(5/4)c+12=2

We move all terms to the left:

(5/4)c+12-(2)=0



Domain of the equation: 4)c!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

(+5/4)c+12-2=0

We add all the numbers together, and all the variables

(+5/4)c+10=0

We multiply parentheses

5c^2+10=0

a = 5; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·5·10
Δ = -200
Delta is less than zero, so there is no solution for the equation

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