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(5/3)x=5x+9
We move all terms to the left:
(5/3)x-(5x+9)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+5/3)x-(5x+9)=0
We multiply parentheses
5x^2-(5x+9)=0
We get rid of parentheses
5x^2-5x-9=0
a = 5; b = -5; c = -9;
Δ = b2-4ac
Δ = -52-4·5·(-9)
Δ = 205
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{205}}{2*5}=\frac{5-\sqrt{205}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{205}}{2*5}=\frac{5+\sqrt{205}}{10} $
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