(5/2x+12)+2=-8/x-6

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Solution for (5/2x+12)+2=-8/x-6 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(5/2)*x+2+12 = -8/x-6 // + -8/x-6

(5/2)*x-(-8/x)+2+6+12 = 0

(5/2)*x+8*x^-1+2+6+12 = 0

5/2*x^1+8*x^-1+20*x^0 = 0

(5/2*x^2+20*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(5/2*x^2+20*x^1+8*x^0) = 0

x^1

(5/2)*x^2+20*x+8 = 0

(5/2)*x^2+20*x+8 = 0

DELTA = 20^2-(4*8*(5/2))

DELTA = 320

DELTA > 0

x = (320^(1/2)-20)/(2*(5/2)) or x = (-320^(1/2)-20)/(2*(5/2))

x = (8*5^(1/2)-20)/5 or x = (-8*5^(1/2)-20)/5

x in { (-8*5^(1/2)-20)/5, (8*5^(1/2)-20)/5}

x in { (-8*5^(1/2)-20)/5, (8*5^(1/2)-20)/5 }

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