(5/2x)=8/(3x-24)

Solution for (5/2x)=8/(3x-24) equation:

(5/2x)=8/(3x-24)

We move all terms to the left:

(5/2x)-(8/(3x-24))=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: (3x-24))!=0

x∈R


We add all the numbers together, and all the variables

(+5/2x)-(8/(3x-24))=0

We get rid of parentheses

5/2x-(8/(3x-24))=0

We calculate fractions


15x/(-42x^2)+(-(8*2x)/(-42x^2)=0


We calculate terms in parentheses: +(-(8*2x)/(-42x^2), so:

-(8*2x)/(-42x^2

We add all the numbers together, and all the variables

-(+8*2x)/(-42x^2

We multiply all the terms by the denominator


-(+8*2x)

We get rid of parentheses

-8*2x

Wy multiply elements

-16x

Back to the equation:

+(-16x)


We get rid of parentheses

15x/(-42x^2)-16x=0

We multiply all the terms by the denominator


-16x*(-42x^2)+15x=0

We multiply parentheses

672x^3+15x=0

We do not support expression: x^3