(5/2)y+y=0

Solution for (5/2)y+y=0 equation:

(5/2)y+y=0


Domain of the equation: 2)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+5/2)y+y=0

We add all the numbers together, and all the variables

y+(+5/2)y=0

We multiply parentheses

5y^2+y=0

a = 5; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·5·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*5}=\frac{-2}{10}
=-1/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*5}=\frac{0}{10}
=0
$