(5/2)x+3=x-4

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Solution for (5/2)x+3=x-4 equation: 



(5/2)x+3=x-4

We move all terms to the left:

(5/2)x+3-(x-4)=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+5/2)x-(x-4)+3=0

We multiply parentheses

5x^2-(x-4)+3=0

We get rid of parentheses

5x^2-x+4+3=0

We add all the numbers together, and all the variables

5x^2-1x+7=0

a = 5; b = -1; c = +7;
Δ = b2-4ac
Δ = -12-4·5·7
Δ = -139
Delta is less than zero, so there is no solution for the equation

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