If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(5/16)y=5/24
We move all terms to the left:
(5/16)y-(5/24)=0
Domain of the equation: 16)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+5/16)y-(+5/24)=0
We multiply parentheses
5y^2-(+5/24)=0
We get rid of parentheses
5y^2-5/24=0
We multiply all the terms by the denominator
5y^2*24-5=0
Wy multiply elements
120y^2-5=0
a = 120; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·120·(-5)
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{6}}{2*120}=\frac{0-20\sqrt{6}}{240} =-\frac{20\sqrt{6}}{240} =-\frac{\sqrt{6}}{12} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{6}}{2*120}=\frac{0+20\sqrt{6}}{240} =\frac{20\sqrt{6}}{240} =\frac{\sqrt{6}}{12} $
| 8z+1=9z-5 | | 3(y+2)+2y=7(1-4y)+9 | | 50c=400 | | 9+3x=-3x(-3-x | | 0.04x+0.03=0.01-0.01 | | -1+2/3x=4 | | C+2c-5=7 | | 3k–2.4=18.6–2k | | 50c=200 | | 2x+6+2x+6=5x+9 | | 1/3n=-15 | | 4.5+4m=m+7.5 | | 4+x=2-1x | | Y-17=3x | | -8=-8n=72 | | 9x-5(3x-12)-4=100-10x | | 4x+23=11 | | 2k+6=9-4k | | x÷3+15=23 | | x/8-9=13 | | 7m-11=5m+1 | | -5(2x+3)+8x=2(4x-7)-10x | | x^2−5x+1=−5 | | 6−2g−1=−13g+2 | | (y/4)(y/4)=9 | | 8w=17.6 | | 5+10(s+2)=35 | | 9x-19-5x=21+6x | | 4x5/3=9 | | u/4+16=44 | | 8.6x+2025=73.96+45x | | 7m–11=5m+1 |