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(5-3x)-(4x+6)=8(x+1)-3(2x+3)
We move all terms to the left:
(5-3x)-(4x+6)-(8(x+1)-3(2x+3))=0
We add all the numbers together, and all the variables
(-3x+5)-(4x+6)-(8(x+1)-3(2x+3))=0
We get rid of parentheses
-3x-4x-(8(x+1)-3(2x+3))+5-6=0
We calculate terms in parentheses: -(8(x+1)-3(2x+3)), so:We add all the numbers together, and all the variables
8(x+1)-3(2x+3)
We multiply parentheses
8x-6x+8-9
We add all the numbers together, and all the variables
2x-1
Back to the equation:
-(2x-1)
-7x-(2x-1)-1=0
We get rid of parentheses
-7x-2x+1-1=0
We add all the numbers together, and all the variables
-9x=0
x=0/-9
x=0
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