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(5-2x)(x+4)=6x-2x
We move all terms to the left:
(5-2x)(x+4)-(6x-2x)=0
We add all the numbers together, and all the variables
(-2x+5)(x+4)-(+4x)=0
We get rid of parentheses
(-2x+5)(x+4)-4x=0
We multiply parentheses ..
(-2x^2-8x+5x+20)-4x=0
We get rid of parentheses
-2x^2-8x+5x-4x+20=0
We add all the numbers together, and all the variables
-2x^2-7x+20=0
a = -2; b = -7; c = +20;
Δ = b2-4ac
Δ = -72-4·(-2)·20
Δ = 209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{209}}{2*-2}=\frac{7-\sqrt{209}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{209}}{2*-2}=\frac{7+\sqrt{209}}{-4} $
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