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(5-10j)/(2+4j)=0
Domain of the equation: (2+4j)!=0We add all the numbers together, and all the variables
We move all terms containing j to the left, all other terms to the right
4j!=-2
j!=-2/4
j!=-1/2
j∈R
(-10j+5)/(4j+2)=0
We multiply all the terms by the denominator
(-10j+5)=0
We get rid of parentheses
-10j+5=0
We move all terms containing j to the left, all other terms to the right
-10j=-5
j=-5/-10
j=1/2
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