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(5-1/4x)=10-(x-1)
We move all terms to the left:
(5-1/4x)-(10-(x-1))=0
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(-1/4x+5)-(10-(x-1))=0
We get rid of parentheses
-1/4x-(10-(x-1))+5=0
We multiply all the terms by the denominator
-((10-(x-1)))*4x+5*4x-1=0
Wy multiply elements
-((10-(x-1)))*4x+20x-1=0
We add all the numbers together, and all the variables
20x-((10-(x-1)))*4x-1=0
We move all terms containing x to the left, all other terms to the right
20x-((10-(x-1)))*4x=1
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