(5+u)(5u+)=0

Solution for (5+u)(5u+)=0 equation:

(5+u)(5u+)=0

We add all the numbers together, and all the variables

(u+5)(+5u)=0

We multiply parentheses ..

(+5u^2+25u)=0

We get rid of parentheses

5u^2+25u=0

a = 5; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·5·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*5}=\frac{-50}{10}
=-5
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*5}=\frac{0}{10}
=0
$