(5+m)(m=9)

Solution for (5+m)(m=9) equation:

(5+m)(m=9)

We move all terms to the left:

(5+m)(m-(9))=0

We add all the numbers together, and all the variables

(m+5)(m-9)=0

We multiply parentheses ..

(+m^2-9m+5m-45)=0

We get rid of parentheses

m^2-9m+5m-45=0

We add all the numbers together, and all the variables

m^2-4m-45=0

a = 1; b = -4; c = -45;
Δ = b2-4ac
Δ = -42-4·1·(-45)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-14}{2*1}=\frac{-10}{2}
=-5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+14}{2*1}=\frac{18}{2}
=9
$