(5+4x)*4x(x)=2500

Solution for (5+4x)*4x(x)=2500 equation:

(5+4x)*4x(x)=2500

We move all terms to the left:

(5+4x)*4x(x)-(2500)=0

We add all the numbers together, and all the variables

(4x+5)*4xx-2500=0

We multiply parentheses

16x^2+20x-2500=0

a = 16; b = 20; c = -2500;
Δ = b2-4ac
Δ = 202-4·16·(-2500)
Δ = 160400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160400}=\sqrt{400*401}=\sqrt{400}*\sqrt{401}=20\sqrt{401}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20\sqrt{401}}{2*16}=\frac{-20-20\sqrt{401}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20\sqrt{401}}{2*16}=\frac{-20+20\sqrt{401}}{32}
$