(5+3x)=(2x+20)

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Solution for (5+3x)=(2x+20) equation: 



(5+3x)=(2x+20)

We move all terms to the left:

(5+3x)-((2x+20))=0

We add all the numbers together, and all the variables

(3x+5)-((2x+20))=0

We get rid of parentheses

3x-((2x+20))+5=0



We calculate terms in parentheses: -((2x+20)), so:

(2x+20)

We get rid of parentheses

2x+20

Back to the equation:

-(2x+20)



We get rid of parentheses

3x-2x-20+5=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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