(5+3)j=24X2

Solution for (5+3)j=24X2 equation:

(5+3)j=24j^2

We move all terms to the left:

(5+3)j-(24j^2)=0

determiningTheFunctionDomain
-24j^2+(5+3)j=0

We add all the numbers together, and all the variables

-24j^2+8j=0

a = -24; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-24)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-24}=\frac{-16}{-48}
=1/3
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-24}=\frac{0}{-48}
=0
$