(5+2y)*2y=149

Solution for (5+2y)*2y=149 equation:

(5+2y)*2y=149

We move all terms to the left:

(5+2y)*2y-(149)=0

We add all the numbers together, and all the variables

(2y+5)*2y-149=0

We multiply parentheses

4y^2+10y-149=0

a = 4; b = 10; c = -149;
Δ = b2-4ac
Δ = 102-4·4·(-149)
Δ = 2484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2484}=\sqrt{36*69}=\sqrt{36}*\sqrt{69}=6\sqrt{69}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-6\sqrt{69}}{2*4}=\frac{-10-6\sqrt{69}}{8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+6\sqrt{69}}{2*4}=\frac{-10+6\sqrt{69}}{8}
$