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D( i )
5-(2*i) = 0
5-(2*i) = 0
5-(2*i) = 0
5-2*i = 0
5-2*i = 0 // - 5
-2*i = -5 // : -2
i = -5/(-2)
i = 5/2
i in (-oo:5/2) U (5/2:+oo)
(2*i+5)/(5-(2*i)) = 0
(2*i+5)/(5-2*i) = 0
2*i+5 = 0 // - 5
2*i = -5 // : 2
i = -5/2
i = -5/2
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