(5+1/2)p=6

Solution for (5+1/2)p=6 equation:

(5+1/2)p=6

We move all terms to the left:

(5+1/2)p-(6)=0


Domain of the equation: 2)p!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(1/2+5)p-6=0

We multiply parentheses

p^2+5p-6=0

a = 1; b = 5; c = -6;
Δ = b2-4ac
Δ = 52-4·1·(-6)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*1}=\frac{-12}{2}
=-6
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*1}=\frac{2}{2}
=1
$