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(5+1+2m)=1/2(8+20m)
We move all terms to the left:
(5+1+2m)-(1/2(8+20m))=0
Domain of the equation: 2(8+20m))!=0We add all the numbers together, and all the variables
m∈R
(2m+6)-(1/2(20m+8))=0
We get rid of parentheses
2m-(1/2(20m+8))+6=0
We multiply all the terms by the denominator
2m*2(20m+8))-(1+6*2(20m+8))=0
Wy multiply elements
4m^2(2+12m(2=0
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