(5)/(x)=(10)/(3x)+4

Solution for (5)/(x)=(10)/(3x)+4 equation:

(5)/(x)=(10)/(3x)+4

We move all terms to the left:

(5)/(x)-((10)/(3x)+4)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 3x+4)!=0

x∈R


We get rid of parentheses

5/x-10/3x-4=0

We calculate fractions


15x/3x^2+(-10x)/3x^2-4=0

We multiply all the terms by the denominator


15x+(-10x)-4*3x^2=0

Wy multiply elements

-12x^2+15x+(-10x)=0

We get rid of parentheses

-12x^2+15x-10x=0

We add all the numbers together, and all the variables

-12x^2+5x=0

a = -12; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-12)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-12}=\frac{-10}{-24}
=5/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-12}=\frac{0}{-24}
=0
$