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(5)/(9)m-1-(1)/(3)m=3
We move all terms to the left:
(5)/(9)m-1-(1)/(3)m-(3)=0
Domain of the equation: 9m!=0
m!=0/9
m!=0
m∈R
Domain of the equation: 3m!=0We add all the numbers together, and all the variables
m!=0/3
m!=0
m∈R
5/9m-1/3m-4=0
We calculate fractions
15m/27m^2+(-9m)/27m^2-4=0
We multiply all the terms by the denominator
15m+(-9m)-4*27m^2=0
Wy multiply elements
-108m^2+15m+(-9m)=0
We get rid of parentheses
-108m^2+15m-9m=0
We add all the numbers together, and all the variables
-108m^2+6m=0
a = -108; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-108)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-108}=\frac{-12}{-216} =1/18 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-108}=\frac{0}{-216} =0 $
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