(5)/(6-2u)

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Solution for (5)/(6-2u) equation: 


D( u )

6-(2*u) = 0

6-(2*u) = 0

6-(2*u) = 0

6-2*u = 0

6-2*u = 0 // - 6

-2*u = -6 // : -2

u = -6/(-2)

u = 3

u in (-oo:3) U (3:+oo)

5/(6-(2*u)) = 0

5/(6-2*u) = 0

5 = 0

u belongs to the empty set

u belongs to the empty set

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