(5)/(6)(x-4)=(1)/(2)(x-2)

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Solution for (5)/(6)(x-4)=(1)/(2)(x-2) equation: 



(5)/(6)(x-4)=(1)/(2)(x-2)

We move all terms to the left:

(5)/(6)(x-4)-((1)/(2)(x-2))=0



Domain of the equation: 6(x-4)!=0

x∈R





Domain of the equation: 2(x-2))!=0

x∈R



We calculate fractions


(10xx/(6(x-4)*2(x-2)))+(-6xx/(6(x-4)*2(x-2)))=0



We calculate terms in parentheses: +(10xx/(6(x-4)*2(x-2))), so:

10xx/(6(x-4)*2(x-2))

We multiply all the terms by the denominator


10xx

Back to the equation:

+(10xx)





We calculate terms in parentheses: +(-6xx/(6(x-4)*2(x-2))), so:

-6xx/(6(x-4)*2(x-2))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)



We get rid of parentheses

10xx-6xx=0

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