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(5)/(2)x+(1)/(4)=(3)/(4)x+2
We move all terms to the left:
(5)/(2)x+(1)/(4)-((3)/(4)x+2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x+2)!=0We get rid of parentheses
x∈R
5/2x-3/4x-2+1/4=0
We calculate fractions
320x/128x^2+(-6x)/128x^2+2x/128x^2-2=0
We multiply all the terms by the denominator
320x+(-6x)+2x-2*128x^2=0
We add all the numbers together, and all the variables
322x+(-6x)-2*128x^2=0
Wy multiply elements
-256x^2+322x+(-6x)=0
We get rid of parentheses
-256x^2+322x-6x=0
We add all the numbers together, and all the variables
-256x^2+316x=0
a = -256; b = 316; c = 0;
Δ = b2-4ac
Δ = 3162-4·(-256)·0
Δ = 99856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{99856}=316$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(316)-316}{2*-256}=\frac{-632}{-512} =1+15/64 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(316)+316}{2*-256}=\frac{0}{-512} =0 $
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