(4z-12)/2=22

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Solution for (4z-12)/2=22 equation: 


z in (-oo:+oo)

(4*z-12)/2 = 22 // - 22

(4*z-12)/2-22 = 0

(4*z-12)/2+(-22*2)/2 = 0

4*z-22*2-12 = 0

4*z-56 = 0

(4*z-56)/2 = 0

(4*z-56)/2 = 0 // * 2

4*z-56 = 0

4*z-56 = 0 // + 56

4*z = 56 // : 4

z = 56/4

z = 14

z = 14

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