(4z-1)(4z-1)=0

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Solution for (4z-1)(4z-1)=0 equation: 



(4z-1)(4z-1)=0

We multiply parentheses ..

(+16z^2-4z-4z+1)=0

We get rid of parentheses

16z^2-4z-4z+1=0

We add all the numbers together, and all the variables

16z^2-8z+1=0

a = 16; b = -8; c = +1;
Δ = b2-4ac
Δ = -82-4·16·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{8}{32}=1/4$

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