(4z+3)=(z-2)

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Solution for (4z+3)=(z-2) equation: 



(4z+3)=(z-2)

We move all terms to the left:

(4z+3)-((z-2))=0

We get rid of parentheses

4z-((z-2))+3=0



We calculate terms in parentheses: -((z-2)), so:

(z-2)

We get rid of parentheses

z-2

Back to the equation:

-(z-2)



We get rid of parentheses

4z-z+2+3=0

We add all the numbers together, and all the variables

3z+5=0

We move all terms containing z to the left, all other terms to the right

3z=-5

z=-5/3

z=-1+2/3

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