(4z+16)+(110)+(31)=180

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Solution for (4z+16)+(110)+(31)=180 equation: 



(4z+16)+(110)+(31)=180

We move all terms to the left:

(4z+16)+(110)+(31)-(180)=0

We add all the numbers together, and all the variables

(4z+16)-39=0

We get rid of parentheses

4z+16-39=0

We add all the numbers together, and all the variables

4z-23=0

We move all terms containing z to the left, all other terms to the right

4z=23

z=23/4

z=5+3/4

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