(4z+11)=115

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Solution for (4z+11)=115 equation: 



(4z+11)=115

We move all terms to the left:

(4z+11)-(115)=0

We get rid of parentheses

4z+11-115=0

We add all the numbers together, and all the variables

4z-104=0

We move all terms containing z to the left, all other terms to the right

4z=104

z=104/4

z=26

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