(4z+1)=(z+3)

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Solution for (4z+1)=(z+3) equation: 



(4z+1)=(z+3)

We move all terms to the left:

(4z+1)-((z+3))=0

We get rid of parentheses

4z-((z+3))+1=0



We calculate terms in parentheses: -((z+3)), so:

(z+3)

We get rid of parentheses

z+3

Back to the equation:

-(z+3)



We get rid of parentheses

4z-z-3+1=0

We add all the numbers together, and all the variables

3z-2=0

We move all terms containing z to the left, all other terms to the right

3z=2

z=2/3

z=2/3

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