(4z+1)=(2z+7)

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Solution for (4z+1)=(2z+7) equation: 



(4z+1)=(2z+7)

We move all terms to the left:

(4z+1)-((2z+7))=0

We get rid of parentheses

4z-((2z+7))+1=0



We calculate terms in parentheses: -((2z+7)), so:

(2z+7)

We get rid of parentheses

2z+7

Back to the equation:

-(2z+7)



We get rid of parentheses

4z-2z-7+1=0

We add all the numbers together, and all the variables

2z-6=0

We move all terms containing z to the left, all other terms to the right

2z=6

z=6/2

z=3

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