(4z+1)+(5z-3)=104

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Solution for (4z+1)+(5z-3)=104 equation: 



(4z+1)+(5z-3)=104

We move all terms to the left:

(4z+1)+(5z-3)-(104)=0

We get rid of parentheses

4z+5z+1-3-104=0

We add all the numbers together, and all the variables

9z-106=0

We move all terms containing z to the left, all other terms to the right

9z=106

z=106/9

z=11+7/9

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