(4y-5)/(2)-(2y-1)/6=6y

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Solution for (4y-5)/(2)-(2y-1)/6=6y equation: 


y in (-oo:+oo)

(4*y-5)/2-((2*y-1)/6) = 6*y // - 6*y

(4*y-5)/2-((2*y-1)/6)-(6*y) = 0

(4*y-5)/2-((2*y-1)/6)-6*y = 0

(4*y-5)/2+(-1*(2*y-1))/6-6*y = 0

(6*(4*y-5))/(2*6)+(-1*2*(2*y-1))/(2*6)+(-6*2*6*y)/(2*6) = 0

6*(4*y-5)-1*2*(2*y-1)-6*2*6*y = 0

20*y-72*y-28 = 0

-52*y-28 = 0

(-52*y-28)/(2*6) = 0

(-52*y-28)/(2*6) = 0 // * 2*6

-52*y-28 = 0

-52*y-28 = 0 // + 28

-52*y = 28 // : -52

y = 28/(-52)

y = -7/13

y = -7/13

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